0=t^2-15t+100

Simple and best practice solution for 0=t^2-15t+100 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 0=t^2-15t+100 equation: 



0=t^2-15t+100

We move all terms to the left:

0-(t^2-15t+100)=0

We add all the numbers together, and all the variables

-(t^2-15t+100)=0

We get rid of parentheses

-t^2+15t-100=0

We add all the numbers together, and all the variables

-1t^2+15t-100=0

a = -1; b = 15; c = -100;
Δ = b2-4ac
Δ = 152-4·(-1)·(-100)
Δ = -175
Delta is less than zero, so there is no solution for the equation

See similar equations:

| H(t)=10+4t+-5t^2 | | H(t)=10+4t+-5t2 | | -2y/3-4=3y/5+6 | | 1.2×1.2=b | | 2x​+4=5+6x​ | | 7y/7=20 | | 0.8^(n)=0.05 | | 1x=9+0.6x | | x=9+0.6x | | m/1-m/2=1/1-m/3-2/3 | | (m-)m-1/2=(1-)(m)-2/3 | | 4-2x/3=3(X+3) | | 0.125x^+2.5x^2=3 | | 9^x=1÷729 | | 8m=1,4 | | 4x-(15-x)=18 | | D2-4D+4))=x3 | | X+(x1.2)=464 | | 312+2x=224+103×x | | 2x+60=62x | | | | | | 2x+41=891 | | 5(x+4)+6(x+3)=11 | | 2(x+3)+3(x+2)=9 | | 6(4x+2)7+3(4x+3)=8 | | 5(3x+2)+8(2x+4)=5 | | 20x-9=4x+15 | | 4x+5+2+3x+2(4x+3)=10 | | 0.0074(4-k)+0.09(k-5)=1 | | 3(2x+8)+4(5x+6)=45 | | 2(4x+7)+6(7x+5)=28 |

Equations solver categories